By Lawrence O Roth; Harry L Field
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Extra info for An introduction to agricultural engineering : a problem-solving approach
Solution: Rearranging Equation (6-4) to solve for T02 gives us: rpm} T02 = TOI x rpm2 = 20 lb-ft 300 rpm x 50rpm = l20lb-ft Notice that the speed of the driven shaft is one-sixth that of the driver shaft. but the torque on the driven shaft is six times that on the driver shaft. This relationship suggests the reason for a tractor transmission. The engine turns at high speed with low torque. and the drive axle turns at low speed with high torque. The transmission uses several different gear pairs to produce different speed-torque combinations at the drive axle.
Large ventilation fans of this type are commonly used in greenhouses, animal bUildings, and other agricultural applications. Problem: Assume that you have a fan and an electric motor, but no pulleys. The fan is designed to operate at 500 rpm, and the electric motor operates at 1725 rpm. What sizes of pulleys will be needed to operate the fan? Solution: First, intuitive reasoning tells us that a large change in speed will require a large difference in pulley diameters. Second, we know that Equation (6-1) includes four Variables, and at this point we only know two, the pulley speeds.
In the carbureted engine fuel is introduced into the air stream as it flows through the carburetor. Shortly after the piston reaches the bottom of the intake stroke. the intake valve closes, thus trapping the air--fuel mixture inside the cylinder. The compreSSion stroke follows. Because the air--fuel mixture is trapped in the cylinder. as the piston returns to the top of the cylinder during this stroke. the air is compressed, and as it is compressed, the temperature rises. As the piston nears the top of the compression stroke, ignition occurs.